How do you solve #6y - ( 6+ 2y ) = 2( y + 1)#?

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Answer 1 · 2017-07-24T01:28:33

#y=4#

Begin by simplifying both sides:

#6ycolor(red)-(6+2y)=color(red)2(y+1)#

Distribute what's in red to each tern inside ()

#6y-6-2y=2y+2#

Combine like terms where possible

#color(red)(6y)-6color(red)(-2y)=2y+2#

#4y-6=2y+2#

Add #6# to both sides

#4ycolor(red)(cancel(-6+6))=2y+2+color(red)6#

#4y=2y+8#

Subtract #2y# from both sides

#4ycolor(red)(-2y)=color(red)(cancel(2y-2y))+8#

#2y=8#

Divide #2# to both sides

#color(red)cancel(2)/color(red)cancel(2)y=8/color(red)2#

#y=4#