How do you solve #(7 1/3) / (9 1/5) = (18 1/3) / x#?

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Answer 1 · 2016-03-23T00:25:16

#x=23#

#(7 1/3)/(9 1/5)=(18 1/3)/x#

Convert the mix fractions first into improper fractions

#(22/3)/(46/5)=(55/3)/x#

then simplify following the rules in division of fractions

#(22/3)*(5/46)=55/(3x)#

#(11/3)*(5/23)=55/(3x)#

#(11*5)/(3*23)=55/(3x)#

Cross multiply

#(3x)*(11)(5)=55(3)(23)#
Divide both sides by # (55)(3)#

#((3x)*(55))/(55*3)=(55(3)(23))/(55*3)#

#((cancel3x)*(cancel55))/(cancel55*cancel3)=(cancel55(cancel3)(23))/(cancel55*cancel3)#

#x=23#

God bless....I hope the explanation is useful.