How do you solve #7(2-p)=14-7p#?

1 Answer
Apr 16, 2018

All real numbers or #(-oo, oo)#

Here's how I did it:

Explanation:

#7(2-p)=14-7p#

First, distribute:
#14-7p=14-7p#

Subtract #14# from both sides of the equation:
#14 - 7p quadcolor(red)(-quad14)=14 - 7p quadcolor(red)(-quad14)#

#-7p = -7p#

Divide both sides by #-7#:

#(-7p)/color(red)(-7) = (-7p)/color(red)(-7)#

#p = p#

Since we know that #p=p# is true, that means that the solution is any real number, or #(-oo, oo)#.

Any real solution will work.

Hope this helps!