How do you solve $7 (2 - p) = 14 - 7 p$ $7(2-p)=14-7p$ ?

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Answer 1 · 2018-04-16T05:40:38

All real numbers or $(- \infty, \infty)$ $(-oo, oo)$

Here's how I did it:

$7 (2 - p) = 14 - 7 p$ $7(2-p)=14-7p$

First, distribute:
$14 - 7 p = 14 - 7 p$ $14-7p=14-7p$

Subtract $14$ $14$ from both sides of the equation:
$14 - 7p quadcolor(red)(-quad14)=14 - 7p quadcolor(red)(-quad14)$

$-7p = -7p$

Divide both sides by $-7$ :

$(-7p)/color(red)(-7) = (-7p)/color(red)(-7)$

$p = p$

Since we know that $p=p$ is true, that means that the solution is any real number, or $(-oo, oo)$ .

Any real solution will work.

Hope this helps!

How do you solve 7(2-p)=14-7p7(2−p)=14−7p7(2-p)=14-7p?