How do you solve #7( 3+ 6x ) \geq 147#?

1 Answer
EZ as pi
Oct 31, 2016

#x >= 3#

Explanation:

Treat inequalities in the same way as an equation unless you multiply or divide by an inequality, in which case the inequality sign changes around.

#7(3+6x) >= 147" "# isolate the bracket. Divide by 7

#3+6x >= 21" "#isolate the term in #x#

#6x >= 21-3#

#6x >= 18" "# divide by 6

#x >= 3#

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