How do you solve #7+ 3x = 6x - 8#?

2 Answers
Jun 23, 2017

#x=15#

Explanation:

#7+3x=6x-8#
Minus both side by 7
#7+3x-7=6x-8-7#
#3x=6x-15#
Minus both side by #6x#
#3x-6x=6x-15-6x#
#-3x=-15#
Multiply both side by #-1#
#3x=15#
divide both side by 3
#(3x)/3=15/3#
#x=5#
Solved
Hope this help!!

Jun 23, 2017

#x=5#

Explanation:

#"collect x-terms on one side of the equation and numeric"#
#"values on the other"#

#"add 8 to both sides"#

#7+8+3x=6xcancel(-8)cancel(+8)#

#rArr15+3x=6x#

#"subtract 3x from both sides"#

#15cancel(+3x)cancel(-3x)=6x-3x#

#rArr15=3x#

#"divide both sides by 3"#

#15/3=(cancel(3) x)/cancel(3)#

#rArrx=5#

#color(blue)"As a check"#

Substitute this value into the equation and if both sides are equal then it is the solution.

#"left side "=7+(3xx5)=7+15=22#

#"right side "=(6xx5)-8=30-8=22#

#rArrx=5" is the solution"#