Question

How do you solve `7^ { 4x } = 255`?

Answer 1

`x=ln(255)/(4ln(7))`

Explanation:

Taking the logarithm on both sides we get
`4xln(7)=ln(255)`
dividing by `4ln(7)` we get the result above.

Answer 2

Take logarithm (base 7) in both sides

`log_7 7^(4x)=log_7 255`

`4xlog_7 7=log_7 255`

`4x=log_7 255`

`x=log_7 255/4=0.712`