How do you solve #7^ { 4x } = 255#?

2 Answers
May 25, 2018

#x=ln(255)/(4ln(7))#

Explanation:

Taking the logarithm on both sides we get
#4xln(7)=ln(255)#
dividing by #4ln(7)# we get the result above.

May 25, 2018

Take logarithm (base 7) in both sides

#log_7 7^(4x)=log_7 255#

#4xlog_7 7=log_7 255#

#4x=log_7 255#

#x=log_7 255/4=0.712#