How do you solve $7^ { 4x } = 255$ ?

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Answer 1 · 2018-05-25T08:31:52

$x=ln(255)/(4ln(7))$

Taking the logarithm on both sides we get
$4xln(7)=ln(255)$
dividing by $4ln(7)$ we get the result above.

Answer 2 · 2018-05-25T08:33:43

Take logarithm (base 7) in both sides

$log_7 7^(4x)=log_7 255$

$4xlog_7 7=log_7 255$

$4x=log_7 255$

$x=log_7 255/4=0.712$

How do you solve 7^ { 4x } = 2557^ { 4x } = 255?