How do you solve #-7- 6x = 2x - 7#?

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Answer 1 · 2017-12-04T03:53:33

See a solution process below:

First, add #color(red)(6x)# and #color(blue)(7)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#-7 - 6x + color(red)(6x) + color(blue)(7) = 2x - 7 + color(red)(6x) + color(blue)(7)#

#-7 + color(blue)(7) - 6x + color(red)(6x) = 2x + color(red)(6x) - 7 + color(blue)(7)#

#0 - 0 = (2 + color(red)(6))x - 0#

#0 = 8x#

Now, divide each side of the equation by #color(red)(8)# to solve for #x# while keeping the equation balanced:

#0/color(red)(8) = (8x)/color(red)(8)#

#0 = (color(red)(cancel(color(black)(8)))x)/cancel(color(red)(8))#

#0 = x#

#x = 0#