How do you solve #7+8x=63#?

2 Answers
Feb 28, 2016

#x=7#

Explanation:

#7+8x=63#

#8x=63 -7#

#8x=56#

#x=56/8#

#x=7#

Feb 28, 2016

The others have shown you the shortcut method. This is the same thing but from first principles.

#x=7#

Explanation:

Given:#" "color(brown)(7+8x=63)#

The objective is to have just one #x# and for that to be on one side of the equals sign and everything else on the other side. In doing this you are saying: This is what one #x# is 'worth' (its value).

#color(blue)("Step 1")#
#color(brown)("Have all the terms with x in them on one side and everything else on the other")#

So we need to 'get rid of the 7 on the left side
We do this by turning it into zero. The thing is; what you do to one side you do to the other to keep numeric balance.

Subtract #color(blue)( 7)# from both sides

#color(brown)(7color(blue)(-7) +8x=63color(blue)(-7))#

#0+8x=56#

#8x=56#

#color(blue)("Step 2")#

Divide both sides by 8. This is the same as #color(blue)(xx1/8)#

#color(brown)(8xcolor(blue)(xx1/8)= 56color(blue)(xx1/8))#

#8/8 x=56/8#

But #8/8 =1# giving

#color(magenta)(x=56/8=7)#