How do you solve #7( b - 1) \leq 2( 2b + 4)#?

1 Answer
May 8, 2017

See a solution process below:

Explanation:

First, expand the terms in parenthesis on both sides of the inequality by multiplying each term within the parenthesis by the term outside the parenthesis:

#color(red)(7)(b - 1) <= color(blue)(2)(2b + 4)#

#(color(red)(7) * b) - (color(red)(7) * 1) <= (color(blue)(2) * 2b) + (color(blue)(2) * 4)#

#7b - 7 <= 4b + 8#

Next, add #color(red)(7)# and subtract #color(blue)(4b)# from each side of the inequality to isolate the #b# term while keeping the inequality balanced:

#-color(blue)(4b) + 7b - 7 + color(red)(7) <= -color(blue)(4b) + 4b + 8 + color(red)(7)#

#(-color(blue)(4) + 7)b - 0 <= 0 + 15#

#3b <= 15#

Now, divide each side of the inequality by #color(red)(3)# to solve for #b# while keeping the inequality balanced:

#(3b)/color(red)(3) <= 15/color(red)(3)#

#(color(red)(cancel(color(black)(3)))b)/cancel(color(red)(3)) <= 5#

#b <= 5#