Question

How do you solve `7=\sqrt{64-x^{2}}`?

Answer 1

`x=+-sqrt(15)`

Explanation:

`7=sqrt(64-x^2)`

Squaring both sides, we get

`49=64-x^2`

`-x^2=49-64`

`-x^2=-15`

`x^2=15`

`x=+-sqrt(15)`