How do you solve #7p - 4p = 12#?

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Answer 1 · 2017-03-30T01:23:49

See the entire solution process below:

First, factor the common terms on the left side of the equation;

#p(7 - 4) = 12#

#p3 = 12#

#3p = 12#

Now, divide each side of the equation by #color(red)(3)# to solve for #p# while keeping the equation balanced:

#(3p)/color(red)(3) = 12/color(red)(3)#

#(color(red)(cancel(color(black)(3)))p)/cancel(color(red)(3)) = 4#

#p = 4#