How do you solve # 7x+1=4x+7#?

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Answer 1 · 2017-06-11T02:01:33

See a solution process below:

Step 1) Subtract #color(red)(1)# and #color(blue)(4x)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#-color(blue)(4x) + 7x + 1 - color(red)(1) = -color(blue)(4x) + 4x + 7 - color(red)(1)#

#(-color(blue)(4) + 7)x + 0 = 0 + 6#

#3x = 6#

Step 2) Divide each side of the equation by #color(red)(3)# to solve for #x# while keeping the equation balanced:

#(3x)/color(red)(3) = 6/color(red)(3)#

#(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) = 2#

#x = 2#