How do you solve #-7x + 5( x - 2) \geq - 22#?

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Answer 1 · 2017-06-17T05:02:32

#x<=6#

Solve:

#-7x+5(x-2)>=-22#

Expand.

#-7x+5x-10>=-22#

Simplify.

#-2x-10>=-22#

Add #10# to both sides.

#-2x-color(red)cancel(color(black)(10))+color(red)cancel(color(black)(10))>=-22+10# #lArr# Cancel the tens.

Simplify.

#-2x>=-12#

Divide both sides by #-2#. This will reverse the inequality.

#(color(red)cancel(color(black)(-2))x)/(color(red)cancel(color(black)(-2)))<=(-12)/(-2)# #lArr# Two negatives make a positive.

Simplify.

#x<=12/2#

Simplify.

#x<=6#