How do you solve #-7y + 3( y + 3) = 17#?

1 Answer
Mar 5, 2017

See the entire solution process below:

Explanation:

First, expand the terms within the parenthesis on the left side of the equation by multiplying each term by #color(red)(3)#:

#-7y + (color(red)(3)xxy) + (color(red)(3)xx3) = 17#

#-7y + 3y + 9 = 17#

Next, combine like terms on the left side of the equation:

#(-7 + 3)y + 9 = 17#

#-4y + 9 = 17#

Then, subtract #color(red)(9)# from each side of the equation to isolate the #y# term while keeping the equation balanced:

#-4y + 9 - color(red)(9) = 17 - color(red)(9)#

#-4y + 0 = 8#

#-4y = 8#

Now, divide each side of the equation by #color(red)(-4)# to solve for #y# while keeping the equation balanced:

#(-4y)/color(red)(-4) = 8/color(red)(-4)#

#(color(red)(cancel(color(black)(-4)))y)/cancel(color(red)(-4)) = -2#

#y = -2#