How do you solve #7y + 4- 2y = 2y + 13 #?

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Answer 1 · 2017-09-19T11:26:48

See a solution process below:

First, group and combine like terms on the left side of the equation:

#7y - 2y + 4 = 2y + 13#

#(7 - 2)y + 4 = 2y + 13#

#5y + 4 = 2y + 13#

Next, subtract #color(red)(4)# and #color(blue)(2y)# from each side of the equation to isolate the #y# term while keeping the equation balanced:

#-color(blue)(2y) + 5y + 4 - color(red)(4) = -color(blue)(2y) + 2y + 13 - color(red)(4)#

#(-color(blue)(2) + 5)y + 0 = 0 + 9#

#3y = 9#

Now, divide each side of the equation by #color(red)(3)# to solve for #y# while keeping the equation balanced:

#(3y)/color(red)(3) = 9/color(red)(3)#

#(color(red)(cancel(color(black)(3)))y)/cancel(color(red)(3)) = 3#

#y = 3#