How do you solve # 7y + 6= 8y#?

1 Answer
smendyka
Jul 9, 2017

See a solution process below:

Explanation:

Subtract #color(red)(7y)# from each side of the equation to solve for #y# while keeping the equation balanced:

#-color(red)(7y) + 7y + 6 = -color(red)(7y) + 8y#

#0 + 6 = (-color(red)(7) + 8)y#

#6 = 1y#

#6 = y#

#y = 6#

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