How do you solve #-8( 2n - 1) = 8- 8n#?
1 Answer
Nov 22, 2016
Explanation:
Distribute the bracket, collect terms in n on the left side of the equation and numeric values on the right side.
#rArr-16n+8=8-8n# add 8n to both sides.
#-16n+8n+8=8cancel(-8n)cancel(+8n)#
#rArr-8n+8=8# subtract 8 from both sides.
#-8ncancel(+8)cancel(-8)=cancel(8)cancel(-8)#
#rArr-8n=0#
#rArrn=0" is the solution"#
