How do you solve #8^(2x-4)=16^(2x+4)#?
Let us take the log in base
we now use the definition of log to solve the two logs and get:
rearrange and solve for
Some exponential equations need to be solved using logs, others can be solved by making the bases or the indices the same.
This is an example of the latter.
Both 8 and 16 are powers of 2, so we can write this equation in terms of a common base on each side.