How do you solve #-8< - 2x + 8\leq 6#?

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Answer 1 · 2018-05-14T21:59:12

#1leqx<8#

Split into two inequalities

A) #-8< -2x+8# and B) #-2x+8leq6#

First part A
subtract 8

#-16 <-2x#
divide by -2

#8>x# (note this changes the inequality)

Then part B
subtract 8

#-2xleq-2#
divide by -2

#xgeq1#