How do you solve #8=3+|10y+5|#?

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Answer 1 · 2014-10-26T11:03:25

#8=3+|10y+5|#

by subtracting #3#,

#Rightarrow 5=|10y+5|#

by removing the absolute value sign,

#Rightarrow{(10y+5=5),(10y+5=-5):}#

(Note: Since the absolute value erases the negative sign, we need to consider both positive and negative values.)

by subtracting #5#,

#Rightarrow{(10y=0),(10y=-10):}#

by dividing by #10#,

#Rightarrow{(y=0),(y=-1):}#

Hence, #y=-1,0#.

I hope that this was helpful.