# How do you solve 8=3+|10y+5|?

Oct 26, 2014

$8 = 3 + | 10 y + 5 |$

by subtracting $3$,

$R i g h t a r r o w 5 = | 10 y + 5 |$

by removing the absolute value sign,

$R i g h t a r r o w \left\{\begin{matrix}10 y + 5 = 5 \\ 10 y + 5 = - 5\end{matrix}\right.$

(Note: Since the absolute value erases the negative sign, we need to consider both positive and negative values.)

by subtracting $5$,

$R i g h t a r r o w \left\{\begin{matrix}10 y = 0 \\ 10 y = - 10\end{matrix}\right.$

by dividing by $10$,

$R i g h t a r r o w \left\{\begin{matrix}y = 0 \\ y = - 1\end{matrix}\right.$

Hence, $y = - 1 , 0$.

I hope that this was helpful.