How do you solve #8- 3= - \frac { 3} { 5} t#?

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Answer 1 · 2016-10-21T08:23:10

#t=-8 1/3#

#8-3=-3/5t#

#5=-3/5t#

Multiply both sides by #5#.

#25=-3t#

Divide both sides by #3#.

#25/3=-t#

Change the value.

#-25/3=t#

#:. -8 1/3=t# or #t=-8 1/3#