How do you solve $8 - 6 (1 - 7 b) = - 82$ $8- 6( 1- 7b ) = - 82$ ?

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Answer 1 · 2016-09-24T17:32:35

Multiply first then isolate $b$ $b$ .

Multiply $8 - 6$ $8-6$ and $(1 - 7 b)$ $(1-7b)$ . You must get $8 - 56 b - 6 + 42 b$ $8-56b-6+42b$ .

Simplify. This will then be: $2 - 14 b$ $2-14b$ .

It will look like: $2 - 14 b = - 82$ $2-14b=-82$

Isolate $b$ $b$

$- 14 b = - 82 - 2$ $-14b=-82-2$

Divide by $- 14$ $-14$ both sides.

Then:

$b = - \frac{84}{- 14}$ $b=-84/-14$

And $b = 6$ $b=6$ .

How do you solve 8−6(1−7b)=−828- 6( 1- 7b ) = - 82?