How do you solve #8( 6x - 22) - 12\geq 52#?

1 Answer
Jul 16, 2017

See a solution process below:

Explanation:

First, expand the terms in parenthesis on the left side of the inequality. Multiply each term within the parenthesis by the term outside the parenthesis:

#color(red)(8)(6x - 22) - 12 >= 52#

#(color(red)(8) xx 6x) - (color(red)(8) xx 22) - 12 >= 52#

#48x - 176 - 12 >= 52#

#48x - 188 >= 52#

Next, add #color(red)(188)# to each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#48x - 188 + color(red)(188) >= 52 + color(red)(188)#

#48x - 0 >= 240#

#48x >= 240#

Now, divide each side of the inequality by #color(red)(48)# to solve for #x# while keeping the inequality balanced:

#(48x)/color(red)(48) >= 240/color(red)(48)#

#(color(red)(cancel(color(black)(48)))x)/cancel(color(red)(48)) >= 5#

#x >= 5#