How do you solve #-8\leq \frac { - 3x + 1} { 4} \leq 2#?

1 Answer
Binayaka C.
Oct 20, 2016

Solution: #-7/3 <= x <= 11# In interval notation; #[-7/3,11]#

Explanation:

# -8 <= (-3x+1)/4 <= 2 or -32 <= (-3x+1) <= 8 or -33 <= -3x <= 7 or 33>=3x>= -7 or 11 >= x >= -7/3 or -7/3 <= x <= 11#
Solution: #-7/3 <= x <= 11# In interval notation; #[-7/3,11]#[Ans]

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