First, use the distributive property to simplify #-8(v+2)#:
#color(blue)(-8(v+2) = (-8 * v) + (-8 * 2) = -8v - 16)#
Put it back into the equation:
#-8v - 16 + 2v + 5 = 6v + 11#
Combine like terms on the left side:
#-6v - 11 = 6v + 11#
Subtract #color(blue)(6v)# from both sides:
#-6v - 11 quadcolor(blue)(-quad6v) = 6v + 11 quadcolor(blue)(-quad6v)#
#-12v - 11 = 11#
Add #color(blue)(11)# to both sides:
#-12v - 11 quadcolor(blue)(+quad11) = 11 quadcolor(blue)(+quad11)#
#-12v = 22#
Divide both sides by #color(blue)(-12)#:
#(-12v)/color(blue)(-12) = 22/color(blue)(-12)#
#v = -22/12#
Divide by #color(blue)2# to simplify:
#v = -22/12 -: color(blue)(2/2)#
Therefore,
#v = -11/6# or about #-1.83# (rounded to nearest hundredth's place)
Hope this helps!
