Question

How do you solve `8^(x-1)<=(1/2)^(2x-1)` using a graph?

Answer 1

`x le 4/5`

Explanation:

First you reduce the expression to the same basis.

Knowing that `8=2^3` and `1/2 = 2^-1` we have

`2^(3(x-1)) le 2^(-(2x-1))`

`2^y` is a monotonically increasing function so this implies in

`3(x-1) le -(2x-1)` or

`5x-4 le 0` so `x le 4/5` is the feasible set