How do you solve #8( x - 2) - 6x = 12#?

1 Answer
Apr 25, 2017

See the entire solution process below:

Explanation:

First, expand the terms in parenthesis on the left side of the equation by multiplying each term within the parenthesis by the term outside the parenthesis:

#color(red)(8)(x - 2) - 6x = 12#

#(color(red)(8) * x) - (color(red)(8) * 2) - 6x = 12#

#8x - 16 - 6x = 12#

Next, we can group and combine like terms on the left side of the equation:

#8x - 6x - 16 = 12#

#(8 - 6)x - 16 = 12#

#2x - 16 = 12#

Then, add #color(red)(16)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#2x - 16 + color(red)(16) = 12 + color(red)(16)#

#2x - 0 = 28#

#2x = 28#

Now, divide each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#(2x)/color(red)(2) = 28/color(red)(2)#

#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = 14#

#x = 14#