How do you solve #8(x-2) = x + 19#?

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Answer 1 · 2018-04-15T18:30:11

#x=5#

We can start by distributing the #8# to both terms in the parenthesis on the left hand side. Doing this, we get:

#8x-16=x+19#

Our next step would be to add #16# to both sides to get:

#8x=x+35#

Next, we can subtract #x# from both sides to get:

#7x=35#

Our last step would be to divide both sides by #7# to get:

#x=5#

Hope this helps!

Answer 2 · 2018-04-15T18:31:08

#x=5#

First expand brackets

#8x-16=x+19#

Next add 16 to both sides

#8x=x+35#

Then take x from both sides

#7x=35#

Finally, divide both sides by 7

#x=5#