How do you solve #80/25 -: -2/3#?

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Answer 1 · 2016-03-31T02:38:58

#-24/5#

#1#. When dividing a fraction by another fraction, take the reciprocal of the second fraction and change the division sign to a multiplication sign.

#80/25-:-2/3#

#=color(blue)80/25xx-3/color(violet)2#

#2#. Since #color(blue)80# and #color(violet)2# can both be divided by a common factor of #2#, their values can be reduced.

#=(color(blue)80color(red)(-:2))/25xx-3/(color(violet)2color(red)(-:2))#

#3#. Simplify.

#=40/25xx-3/1#

#4#. Solve.

#=-120/25#

#5#. Since #120# and #25# can both be divided by #5#, the fraction reduces.

#=(-120color(red)(-:5))/(25color(red)(-:5))#

#=color(green)(|bar(ul(color(white)(a/a)-24/5color(white)(a/a)|)))#