How do you solve #864\leq \frac { b } { - 3} + 862#?

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Answer 1 · 2017-03-29T16:30:41

#b<-6#

Subtract 862 from both sides:

#864-862 <= b/-3#

#2<=b/-3#

Now multiply by #-3#. Remember that when you multiply by a negative, the greater than symbol or equal to symbol becomes a less than symbol.

#-6>b#

For personal preference, rewrite this so #b# is on the left side:

#b<-6#