How do you solve #-8a + 37< 5( 1- 8a )#?

1 Answer
Jim G.
Apr 27, 2018

#a< -1#

Explanation:

#"distribute parenthesis on right side of inequality"#

#-8a+37<5-40a#

#"collect terms in a on left and numeric values on right"#

#"add "40a" to both sides"#

#-8a+40a+37<5cancel(-40a)cancel(+40a)#

#rArr32a+37<5#

#"subtract "37" from both sides"#

#32acancel(+37)cancel(-37)<5-37#

#rArr32a< -32#

#"divide both sides by "32#

#(cancel(32) a)/cancel(32)<(-32)/32#

#rArra< -1" is the solution"#

#a in(-oo,-1)larrcolor(blue)"in interval notation"#

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