How do you solve 8abs(x+8)+ 9 > 6?

To solve: $8 \left\mid x + 8 \right\mid + 9 > 6$
We need to make $8 \left\mid x + 8 \right\mid > 6 - 9 = - 3$
But for every possible number $x$, we know that $\left\mid x \right\mid \ge 0$ so for every possible value of $x$, we have $8 \left\mid x + 8 \right\mid \ge 0 > - 3$