How do you solve #8ln(3x)=48#?

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Answer 1 · 2017-06-02T07:44:27

#x=e^6/3~=134.48#

#8ln(3x)=48#

Divide by 8:

#ln(3x)=6#

Take the inverse function (i.e. place both sides as an exponent to #e#). This will cancel the #ln#.

#e^ln(3x)=e^6#

Keep in mind that #e# is a number and so we can treat it like any other number.

#3x=e^6#

#x=e^6/3~=134.48#