How do you solve $8 p - 4 p - (p - 7) + 9 p + 6 = 12 p$ $8p - 4p - ( p - 7) + 9p + 6= 12p$ ?

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Answer 1 · 2016-10-19T23:16:51

This equation has no solution.

Begin by distributing the understood $- 1$ $-1$ :

$8 p - 4 p - (p - 7) + 9 p + 6 = 12 p$ $8p - 4p -(p - 7) + 9p + 6 = 12p$
$8 p - 4 p - p + 7 + 9 p + 6 = 12 p$ $8p - 4p - p + 7 + 9p + 6 = 12p$

Now simplify the left side of the equation by combining like terms:

$12 p + 13 = 12 p$ $12p + 13 = 12p$

Now subtract $12 p$ $12p$ from both sides of the equation, in an attempt to get the variable terms together:

$12 p - 12 p + 13 = 12 p - 12 p$ $12p - 12p + 13 = 12p - 12p$
$13 = 0$ $13 = 0$

However, the variable terms were completely eliminated, and $13$ $13$ is never equal to $0$ $0$ , so

$13 \neq 0$ $13 != 0$

is the result. This means that this equation has no solution.

How do you solve 8p - 4p - ( p - 7) + 9p + 6= 12p8p−4p−(p−7)+9p+6=12p8p - 4p - ( p - 7) + 9p + 6= 12p?