How do you solve #8u + 7= - 11+ 6u#?

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Answer 1 · 2017-06-21T22:45:50

See a solution process below:

First, subtract #color(red)(7)# and #color(blue)(6u)# from each side of the equation to isolate the #u# term while keeping the equation balanced:

#8u + 7 - color(red)(7) - color(blue)(6u) = -11 + 6u - color(red)(7) - color(blue)(6u)#

#8u - color(blue)(6u) + 7 - color(red)(7) = -11 - color(red)(7) + 6u - color(blue)(6u)#

#(8 - color(blue)(6))u + 0 = -18 + 0#

#2u = -18#

Now, divide each side of the equation by #color(red)(2)# to solve for #u# while keeping the equation balanced:

#(2u)/color(red)(2) = -18/color(red)(2)#

#(color(red)(cancel(color(black)(2)))u)/cancel(color(red)(2)) = -9#

#u = -9#