How do you solve #8v = 2( 4v + 2)#?

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Answer 1 · 2017-06-13T21:36:56

See a solution process below:

First, divide each side of the equation by #color(red)(2)# to eliminate the parenthesis while keeping the equation balanced:

#(8v)/color(red)(2) = (2(4v + 2))/color(red)(2)#

#4v = 4v + 2#

Now, subtract #color(red)(4v)# from each side of the equation:

#-color(red)(4v) + 4v = -color(red)(4v) + 4v + 2#

#0 = 0 + 2#

#0 != 2#

Because #0# does not equal #2# there is no solution to this problem. Or, the solution is the empty or null set: #{O/}#