Question

How do you solve `-8x - 10 = 4x + 14`?

Answer 1

`x=-2`

Explanation:

`-8x-10=4x+14`

`:.=-8x-4x=14+10`

`:.-12x=24`

`:.-x=cancel24^2/cancel12^1`

:.`-x=2`

multiply both sides by`-1`

`:.-1xx-x=2xx-1`

`:.x=-2`

~~~~~~~~~~~~~

check:-

substitute `x=-2`

`-8(-2)-10=4(-2)+14`

`16-10=-8+14`

`6=6`

Answer 2

`x = -2`

Explanation:

`-8x - 10 = 4x + 14`

Move all variables to one side.

`-8x = 4x + 24`

`-12x = 24`

`x = -2`

Answer 3

`x=-2`

Explanation:

`"collect terms in x on the left and numeric values on the"`
`"right"`

`"subtract 4x from both sides"`

`-8x-4x-10=cancel(4x)cancel(-4x)+14`

`rArr-12x-10=14`

`"add 10 to both sides"`

`-12xcancel(-10)cancel(+10)=14+10`

`rArr-12x=24`

`"divide both sides by "-12`

`(cancel(-12) x)/cancel(-12)=24/(-12)`

`rArrx=-2`

`color(blue)"As a check"`

Substitute this value into the equation and if the left side is equal to the right side then it is the solution.

`"left "=(-8xx-2)-10=16-10=6`

`"right "=(4xx-2)+14=-8+14=6`

`rArrx=-2" is the solution"`