Question

How do you solve `8x ^ { 2} + 5x = 0`?

Answer 1

`x=0" or "x=-5/8`

Explanation:

`"take out a "color(blue)"common factor "x`

`rArrx(8x+5)=0`

`"equate each factor to zero and solve for x"`

`rArrx=0`

`8x+5=0rArrx=-5/8`