How do you solve 8x+5y=184, x-y=3 using substitution?

Mar 30, 2016

$\left(x , y\right) \in \left\{\left(\frac{199}{13} , \frac{160}{13}\right)\right\} \subset \mathbb{Q} \times \mathbb{Q}$

Explanation:

The second equation have coefficients 1 and -1. Do you want an equation in x? Isolate y.
$x - 3 = y$
From the first,
$8 x + 5 \left(x - 3\right) = 184$
$8 x + 5 x - 15 = 184$
$13 x = 184 + 15$
$x = \frac{199}{13}$
$y = x - 3 = \frac{199}{13} - 3 = \frac{160}{13}$