How do you solve #8x + 8( 6x - 2) = - 8( - 6x - 8)#?

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Answer 1 · 2016-11-19T18:54:12

#x = 10#

Step 1) Expand the terms in parenthesis:

#8x + 48x - 16 = 48x + 64#

Step 2) Combine like terms:

#56x - 16 = 48x + 64#

Step 3) Solve for #x# while keeping the equation balanced:

#56x - 16 + 16 - 48x = 48x + 64 + 16 - 48x#

#8x = 80#

#(8x)/8 = 80/8#

#x = 10#