Question

How do you solve `8y + 30= 2( 4y + 3)`?

Answer 1

No Solution or `cancel0`.

Explanation:

First, use the distributive to simplify `color(blue)(2(4y+3))`:

Following this image:
`color(blue)(2(4y+3) = (2 * 4y) + (2 * 3) = 8y + 6)`

Let's put that back into the equation:
`8y + 30 = 8y + 6`

Now subtract `color(blue)(8y)` from both sides:
`8y + 30 quadcolor(blue)(-quad8y) = 8y + 6 quadcolor(blue)(-quad8y)`

`30 = 6`

Oh no! Our variable is gone! This means we have to look at our equation and see if it is true.

Is it true that `30 = 6`? No. That means there is No Solution, or `cancel0`.