Question

How do you solve `-8y - 34= - 6( y + 3)`?

Answer 1

`y=-8`

Explanation:

Distribute the bracket on the right side of the equation.

`rArr-8y-34=-6y-18`

collect terms in y on the left side and numeric values on the right side.

add 6y to both sides.

`-8y+6y-34=cancel(-6y)cancel(+6y)-18`

`rArr-2y-34=-18`

add 34 to both sides.

`-2ycancel(-34)cancel(+34)=-18+34`

`rArr-2y=16`

divide both sides by - 2

`(cancel(-2) y)/cancel(-2)=16/(-2)`

`rArry=-8`

`color(blue)"As a check"`

Substitute this value into the equation and if the left side is equal to the right side then it is the solution.

`"left side "=(-8xx-8)-34=64-34=30`

`"right side "=-6(-8+3)=-6xx-5=30`

`rArry=-8" is the solution"`