How do you solve #9- 2 x < 7 + 2 ( x - 3 )#?

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Answer 1 · 2016-12-06T21:24:49

#x > 2#

Step 1) Expand the terms in parenthesis:

#9 - 2x < 7 + 2x - 6#

#9 - 2x < 1 + 2x#

Next isolate the #x# terms on one side of the inequality and the constants on the other side of the inequality while keeping the inequality balanced:

#9 - 2x + 2x - 1 < 1 + 2x + 2x - 1#

#9 - 1 < 2x + 2x#

#8 < 4x#

Now, solve for #x# while keeping the inequality balanced:

#8/4 < (4x)/4#

#2< x#

Finally, to state the solution in terms of #x# we need to "flip" the inequality:

#x > 2#