How do you solve #9- 2c + c= - 13#?

1 Answer
Feb 27, 2017

See the entire solution process below:

Explanation:

First, combine like terms on the left side of the equation:

#9 + (-2 + 1)c = -13#

#9 + (-1)c = -13#

#9 - c = -13#

Next, subtract #color(red)(9)# from each side of the equation to isolate the #c# term while keeping the equation balanced:

#-color(red)(9) + 9 - c = -color(red)(9) - 13#

#0 - c = -22#

#-c = -22#

Now, multiply each side of the equation by #color(red)(-1)# to solve for #c# while keeping the equation balanced:

#color(red)(-1) xx -c = color(red)(-1) xx -22#

#c = 22#