How do you solve #9 + 3/4x = 7/8x - 10#?

3 Answers
Jumbotron
Apr 20, 2018

See a solution process below

Explanation:

#9 + 3/4x = 7/8x - 10#

Multiply through by their LCM

#4 = 2 xx 2#

#8 = 2 xx 2 xx 2#

LCM #= 2 xx 2 xx 2#

The LCM #=8#

Therefore;

#8(9) + 8(3/4x) = 8(7/8x) - 8(10)#

#72 + 2(3x) = 7x - 80#

#72 + 6x = 7x - 80#

Collect like terms..

#6x - 7x = - 80 - 72#

#-x = -152#

#x = 152#

Jumbotron
Apr 20, 2018

See a solution process below

Explanation:

#9 + 3/4x = 7/8x - 10#

Multiply through by their LCM

#4 = 2 xx 2#

#8 = 2 xx 2 xx 2#

LCM #= 2 xx 2 xx 2#

The LCM #=8#

Therefore;

#8(9) + 8(3/4x) = 8(7/8x) - 8(10)#

#72 + 2(3x) = 7x - 80#

#72 + 6x = 7x - 80#

Collect like terms..

#6x - 7x = - 80 - 72#

#-x = -152#

#x = 152#

Jumbotron
Apr 20, 2018

See a solution process below

Explanation:

#9 + 3/4x = 7/8x - 10#

Multiply through by their LCM

#4 = 2 xx 2#

#8 = 2 xx 2 xx 2#

LCM #= 2 xx 2 xx 2#

The LCM #=8#

Therefore;

#8(9) + 8(3/4x) = 8(7/8x) - 8(10)#

#72 + 2(3x) = 7x - 80#

#72 + 6x = 7x - 80#

Collect like terms..

#6x - 7x = - 80 - 72#

#-x = -152#

#x = 152#

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