How do you solve #-9< 3n < 18#?

2 Answers
Mar 11, 2017

#-3 < n < 6#

Explanation:

#color(blue)"Isolate"# n in the middle interval and have numeric values in the 2 outer intervals.

divide ALL 3 intervals by 3

#(-9)/3 < (cancel(3) n)/cancel(3) < 18/3#

#rArr-3 < n < 6" is the solution"#

Divide all terms by #3# to solve for #n#.

# -3 < n < 6 #

Explanation:

Dividing by a positive does not affect the inequality signs.

# -9/3 = -3#

# (3n)/3 = n#

# 18/3 = 6# so

# -3 < n < 6 #