How do you solve #9( 3x ) = 7( x + 20)?#

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Answer 1 · 2017-11-04T00:59:31

#x=7#

Begin by distributing #9# to #3x# and #7# to #(x+20)#

#9(3x)=7(x+20)#

#27x=7x+140#

Subtract #7x# from both sides

#27xcolor(red)(-7x)=cancel(7xcolor(red)(-7x))+140#

#20x=140#

Divide #20# from both sides:

#cancel20/cancelcolor(red)20x=140/color(red)20#

#x=7#