How do you solve #(9+ 53- 2) \div 30+ 5#?

1 Answer
Nityananda
Oct 6, 2016

7

Explanation:

As per simplification rules,first we have to work on first brake. Thereafter as peo 'BODMAS' i.e. 'B'- stands for Bracket, 'O' - stands for Or, 'D'- stands for Divide, 'M'- stands for multiplication, 'A' - stands for addition and 'S'- stands for subtraction.
Hence, #(62-2)-:30+5 = 60-:30+5 =2+5=7#

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