How do you solve #(-9+a)/15 > 1#?

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Answer 1 · 2017-07-08T02:55:07

See a solution process below:

First, multiply each side of the inequality by #color(red)(15)# to eliminate the fraction while keeping the inequality balanced:

#color(red)(15) xx (-9 + a)/15 > color(red)(15) xx 1#

#cancel(color(red)(15)) xx (-9 + a)/color(red)(cancel(color(black)(15))) > 15#

#-9 + a > 15#

Now, add #color(red)(9)# to each side of the inequality to solve for #a# while keeping the inequality balanced:

#color(red)(9) - 9 + a > color(red)(9) + 15#

#0 + a > 24#

#a > 24#