# How do you solve 9/(b+5)=3/(b-3)?

Nov 27, 2016

$b = 7$

#### Explanation:

$\frac{9}{b + 5} = \frac{3}{b - 3}$

Cross multiply:
$9 \left(b - 3\right) = 3 \left(b + 5\right)$

Distribute:
$9 b - 27 = 3 b + 15$

Solve for b:
$6 b = 42$

$b = 7$

*Make sure the answer works in the original function, and make sure you don't divide by zero.